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Poisson Distribution

Master it step by step with milestone learning
probability
poisson distribution
discrete distribution
rare events
poisson process
Try this concept yourself
한국어
What you will be able to do
Foundations
  • • Understand the basic idea of the Poisson distribution and the situations where it applies
  • • Compute probabilities in simple Poisson distribution problems
  • • Model rare real-life events with the Poisson distribution
Deeper study
  • • Understand and use the probability mass function of the Poisson distribution
  • • Understand why the mean and variance of a Poisson distribution are equal
  • • Apply the Poisson distribution in fields such as traffic, telecommunications, and quality control
Real-world practice
  • • Understand and use the properties of the Poisson process and its extended models
  • • Apply the relationship between the Poisson and gamma distributions in Bayesian methods
  • • Design Poisson models for complex real-world problems and use them in decision-making
At a glance

The Poisson distribution is a discrete probability distribution for the number of rare, independent events that occur in a fixed interval of time or space at a constant average rate λ.

You can verify this hands-on in the NumLM interactive lab (Korean).

한국어

Learning roadmap

Click a step to view its content

Foundations
Definitions and core principles
About 25 min
Open
Deeper study
Derivations and worked examples
About 35 min
Open
Real-world practice
Real cases and advanced applications
About 45 min

Progress (completed levels)

0%

Basic: What Is the Poisson Distribution?

Difficulty 3/5
About 25 min

The Poisson distribution models how many times a rare event occurs within a fixed interval of time or space. You use it when events happen independently of one another at a constant average rate.

Poisson distribution (λ=3) — events per unit of timeProbability that a rare event averaging λ per unit occurs k times. Slightly right-skewed shape5.0%014.9%122.4%222.4%316.8%410.1%55.0%6789101112Number of occurrences kMean = λ = 3Key property of the Poisson: mean and variance are both λ (standard deviation = √λ ≈ 1.73)
Key points
  • Rare events occurring within a fixed interval of time or space
  • Events occur independently of one another
  • The average rate of occurrence (λ) is constant
  • The probability of two events occurring at exactly the same instant is 0
A simple example

If a phone rings 4 times per hour on average (λ=4), the probability that it rings exactly 3 times in a given hour is P(X=3) = e⁻⁴ × 4³ ÷ 3! = 0.0183 × 64 ÷ 6 ≈ 0.195

Check your understanding

Answer:

In a Poisson distribution the mean and the variance are equal. Both are equal to the parameter λ.

Answer:

Use it to model counts of rare, independent events — for example the number of traffic accidents, radioactive decays, or customer arrivals in a given period.

The probability mass function of the Poisson distribution Loading... is Loading..., where Loading... is the average rate of occurrence and Loading... is Euler's number. For small Loading... the distribution is strongly right-skewed; as Loading... grows it becomes more symmetric, and once Loading... it can be approximated by a normal distribution.

Mathematical formula

Loading... is the average rate of occurrence, Loading... is the actual number of occurrences Loading..., and Loading... is Euler's number, approximately Loading.... Loading... is the factorial of Loading....

Learn through examples
Example 1: Traffic Safety Analysis

An intersection averages 2 traffic accidents per month

Poisson(2): probability of 0 accidents in a month
P(X=0) = 2⁰e⁻² ÷ 0! = 1 × 0.1353 ÷ 1 = 0.1353 (13.5%)
Probability of 3 or more accidents in a month
P(X≥3) = 1 - P(X≤2) = 1 - 0.677 = 0.323 (32.3%)

Answer:

The probability of an accident-free month is 13.5%, and the probability of 3 or more accidents is 32.3%.

Even with an average of 2 accidents per month, a month with 3 or more accidents happens roughly one month in three (32.3%). That is why a cluster of accidents in one month should not lead you straight to the conclusion that "the intersection has become dangerous" — it is natural variation even when the rate λ has not changed. By the same logic, an accident-free month (13.5%) does not prove that a safety measure worked.

Example 2: Call Center Operations

A call center receives 15 calls per hour on average

Poisson(15): probability of 20 or more calls in an hour
Using the normal approximation (λ≥10): N(15, 15)
P(X≥20) ≈ P(Z ≥ (19.5-15)/√15) ≈ P(Z ≥ 1.16) ≈ 0.123

Answer:

The probability of receiving 20 or more calls in an hour is about 12.3%.

The question asks about "20 or more", yet the calculation uses 19.5 — that is the continuity correction. When you approximate a discrete distribution (Poisson) with a continuous one (normal), you shift the boundary by 0.5. Without the correction, (20−15)/√15 ≈ 1.29 gives a probability of about 9.8%, an underestimate. Even though λ ≥ 10 makes the approximation itself reasonable, whether or not you apply the continuity correction changes the answer.

Example 3: Quality Control

A fabric averages 0.8 defects per square meter

Poisson(0.8): probability of no defects
P(X=0) = 0.8⁰e⁻⁰·⁸ ÷ 0! = 0.449 (44.9%)
Probability of 2 or more defects
P(X≥2) = 1 - P(X=0) - P(X=1) = 1 - 0.449 - 0.359 = 0.192

Answer:

The probability of a defect-free square meter is 44.9%, and the probability of 2 or more defects is 19.2%.

Even though the average is below one defect (0.8), the chance of a defect-free piece is only 44.9% — more than half of the pieces have at least one defect. Also, if you inspect 2 m² instead of 1 m², λ becomes 1.6 and the defect-free probability shrinks multiplicatively to e⁻¹·⁶ = (0.449)² ≈ 20.2%. In a Poisson model, whenever you change the unit of observation (area or time), λ must scale in proportion.

Case study: Power Outage Forecasting for an Electric Utility
Background

A major electric utility in South Korea faces a rising risk of outages as climate change brings more extreme weather and electricity demand surges. To respond efficiently and position resources in advance, the company urgently needs a data-driven outage forecasting system.

The problem

The existing experience-based approach struggles to cope with unpredictable outages. The utility needs to quantify outage patterns by season and weather conditions and build a proactive response system on top of that analysis.

The data

Five years of outage data (monthly aggregates):
Normal periods (spring/fall): mean 1.8 outages per month, standard deviation 1.3
Summer (June–August): mean 3.2 per month, up to 12 during heat waves
Winter (December–February): mean 2.1 per month, up to 8 during cold snaps
Typhoon season (July–September): mean 8.5 per month, up to 25 under a direct typhoon hit
Additional variables: temperature, humidity, wind speed, electricity demand, equipment age

Method

Step 1: Seasonal Poisson models
• Normal periods: Loading...
• Summer: Loading...
• Winter: Loading...
• Typhoon season: Loading...
Step 2: Set a threshold and compute probabilities
• Trigger for emergency operations: 5 or more outages in a month
• Assess risk by computing Loading...
Step 3: Bayesian real-time updating
• Gamma prior: Loading...
• Poisson likelihood + gamma prior → gamma posterior
• Update the estimate of Loading... as outages occur in real time

Solution and results

Risk assessment:
• Normal periods: Loading... (2.4% - low risk)
• Summer: Loading... (17.1% - medium risk)
• Winter: Loading... (6.8% - low-to-medium risk)
• Typhoon season: Loading... (94.6% - high risk)
Resource deployment strategy:
Normal periods: 2 standard repair crews on standby
Summer/winter: 1 additional repair crew held in reserve
Typhoon season: 5 emergency repair crews plus external contractors on standby
Real-time monitoring:
• 2 outages in the first 3 days of the month → Bayesian update
• Expected outages by month-end: 8.5 before the update → 11.2 after

Operational results (first year after launch):
• Average restoration time: 4.2 hours → 2.8 hours (33% shorter)
• Emergency response accuracy: 67% → 89% (up 22 percentage points)
• Customer satisfaction: 3.2 → 4.1 (on a 5-point scale)
• Unnecessary resource mobilization: 45% → 18% (down 27 percentage points)
Cost impact:
• Annual emergency response costs cut by 15% (about KRW 1.2 billion)
• Social cost of outages reduced by 25%

Conclusion:

A forecasting system built on the Poisson distribution let the utility quantify outage risk and deploy resources efficiently. Bayesian updating in particular allowed it to adapt to changing conditions in real time, improving both the reliability and the economics of the power supply.

References
  • Poisson, S.-D. (1837), Recherches sur la probabilité des jugements en matière criminelle et en matière civile, Paris: Bachelier — the original work in which the Poisson distribution first appears
  • von Bortkiewicz, L. (1898), Das Gesetz der kleinen Zahlen, Leipzig: B. G. Teubner — the classic first serious application of the Poisson distribution to rare events, using data on Prussian cavalry deaths from horse kicks
  • Kingman, J. F. C. (1993), Poisson Processes, Oxford Studies in Probability 3, Oxford: Clarendon Press — the standard reference on Poisson processes (independent increments, exponential inter-arrival times)
  • Cameron, A. C. & Trivedi, P. K. (2013), Regression Analysis of Count Data (2nd ed.), Cambridge: Cambridge University Press — the standard textbook on count data, covering the limits of the Poisson model (overdispersion, zero inflation) and its alternatives
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